# Unemployment: Ocala, FL Metropolitan Statistical Area (U)

Unemployment: Ocala, FL Metropolitan Statistical Area (U) was up 21.2% year on year in September 2025, compared with 12.7% in August 2025.
The level stood at 8,773.0 thousands.
That is the highest reading since July 2024.
Over the past ten years it has ranged from −54.4% (May 2021) to 203.4% (May 2020), averaging 3.5%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-36100.UNEMPLVL.M.NSA`
- Frequency: monthly
- Units: thousands
- Coverage: 1990-01-01 to 2026-09-01 (440 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/unemployment-ocala-fl-metropolitan-statistical-area-u

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 8,773.0 thousands | — |
| August 2026 | 9,289.0 thousands | — |
| July 2026 | 9,370.0 thousands | — |
| June 2026 | 9,241.0 thousands | — |
| May 2026 | 8,933.0 thousands | — |
| April 2026 | 9,249.0 thousands | — |
| March 2026 | 9,108.0 thousands | — |
| February 2026 | 9,946.0 thousands | — |
| January 2026 | 10,271 thousands | — |
| December 2025 | 9,124.0 thousands | — |
| November 2025 | 10,069 thousands | — |
| September 2025 | 8,648.0 thousands | 21.2 |
| August 2025 | 8,634.0 thousands | 12.7 |
| July 2025 | 8,290.0 thousands | 8.2 |
| June 2025 | 7,904.0 thousands | 10.5 |
| May 2025 | 7,079.0 thousands | 17.3 |
| April 2025 | 6,663.0 thousands | 15.8 |
| March 2025 | 6,789.0 thousands | 12.2 |
| February 2025 | 7,016.0 thousands | 10.9 |
| January 2025 | 7,155.0 thousands | 8.5 |
| December 2024 | 6,282.0 thousands | 11.5 |
| November 2024 | 7,000.0 thousands | 17.4 |
| October 2024 | 6,976.0 thousands | 13.9 |
| September 2024 | 7,134.0 thousands | 13.3 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-36100.UNEMPLVL.M.NSA"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-36100.UNEMPLVL.M.NSA",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```