# Unemployment: Erie, PA Metropolitan Statistical Area (U)

Unemployment: Erie, PA Metropolitan Statistical Area (U) was up 29.2% year on year in September 2025, compared with 11.9% in August 2025.
The level stood at 4,014.0 thousands.
That is the highest reading since March 2021.
Over the past ten years it has ranged from −54.8% (Apr 2021) to 300.9% (Apr 2020), averaging 4.1%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-21500.UNEMPLVL.M.NSA`
- Frequency: monthly
- Units: thousands
- Coverage: 1990-01-01 to 2026-09-01 (440 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/unemployment-erie-pa-metropolitan-statistical-area-u

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 4,014.0 thousands | — |
| August 2026 | 5,085.0 thousands | — |
| July 2026 | 4,813.0 thousands | — |
| June 2026 | 4,961.0 thousands | — |
| May 2026 | 5,083.0 thousands | — |
| April 2026 | 4,847.0 thousands | — |
| March 2026 | 5,859.0 thousands | — |
| February 2026 | 6,487.0 thousands | — |
| January 2026 | 6,115.0 thousands | — |
| December 2025 | 5,277.0 thousands | — |
| November 2025 | 5,211.0 thousands | — |
| September 2025 | 5,486.0 thousands | 29.2 |
| August 2025 | 6,540.0 thousands | 11.9 |
| July 2025 | 6,007.0 thousands | 7.3 |
| June 2025 | 5,622.0 thousands | 6.0 |
| May 2025 | 5,085.0 thousands | 13.9 |
| April 2025 | 4,922.0 thousands | 14.6 |
| March 2025 | 5,860.0 thousands | 12.2 |
| February 2025 | 6,263.0 thousands | 6.5 |
| January 2025 | 6,234.0 thousands | 10.7 |
| December 2024 | 5,337.0 thousands | 15.4 |
| November 2024 | 4,666.0 thousands | 8.8 |
| October 2024 | 4,621.0 thousands | 4.3 |
| September 2024 | 4,247.0 thousands | 1.4 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-21500.UNEMPLVL.M.NSA"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-21500.UNEMPLVL.M.NSA",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```