# Labor Force: Muskegon-Norton Shores, MI Metropolitan Statistical Area (U)

Labor Force: Muskegon-Norton Shores, MI Metropolitan Statistical Area (U) was down 0.3% year on year in September 2025, compared with −0.2% in August 2025.
The level stood at 77,809 thousands.
That is the lowest reading since October 2021.
Over the past ten years it has ranged from −8.9% (Jun 2021) to 5.9% (Jun 2020), averaging 1.0%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-34740.LF.M.NSA`
- Frequency: monthly
- Units: thousands
- Coverage: 1990-01-01 to 2026-09-01 (440 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/labor-force-muskegon-norton-shores-mi-metropolitan-statistical-area-u

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 77,809 thousands | — |
| August 2026 | 79,983 thousands | — |
| July 2026 | 80,373 thousands | — |
| June 2026 | 79,585 thousands | — |
| May 2026 | 80,417 thousands | — |
| April 2026 | 79,557 thousands | — |
| March 2026 | 81,295 thousands | — |
| February 2026 | 81,636 thousands | — |
| January 2026 | 82,243 thousands | — |
| December 2025 | 82,162 thousands | — |
| November 2025 | 83,510 thousands | — |
| September 2025 | 85,320 thousands | −0.3 |
| August 2025 | 86,788 thousands | −0.2 |
| July 2025 | 87,499 thousands | −0.3 |
| June 2025 | 87,177 thousands | 0.2 |
| May 2025 | 86,725 thousands | 1.0 |
| April 2025 | 84,892 thousands | 1.0 |
| March 2025 | 85,039 thousands | 1.3 |
| February 2025 | 84,252 thousands | 1.4 |
| January 2025 | 84,551 thousands | 2.0 |
| December 2024 | 84,560 thousands | 2.4 |
| November 2024 | 85,262 thousands | 1.9 |
| October 2024 | 84,849 thousands | 1.8 |
| September 2024 | 85,554 thousands | 2.7 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-34740.LF.M.NSA"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-34740.LF.M.NSA",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```