# Employment: Town of Pecos, TX Micropolitan Statistical Area (U)

Employment: Town of Pecos, TX Micropolitan Statistical Area (U) was up 4.4% year on year in September 2025, compared with 3.9% in August 2025.
The level stood at 6,310.0 thousands.
That is the highest reading since April 2024.
Over the past ten years it has ranged from −32.6% (Jun 2020) to 39.5% (Feb 2018), averaging 3.0%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-45880.EMP.M.NSA`
- Frequency: monthly
- Units: thousands
- Coverage: 1990-01-01 to 2026-09-01 (440 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/employment-town-of-pecos-tx-micropolitan-statistical-area-u

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 6,310.0 thousands | — |
| August 2026 | 6,392.0 thousands | — |
| July 2026 | 6,354.0 thousands | — |
| June 2026 | 6,332.0 thousands | — |
| May 2026 | 6,379.0 thousands | — |
| April 2026 | 6,404.0 thousands | — |
| March 2026 | 6,268.0 thousands | — |
| February 2026 | 6,227.0 thousands | — |
| January 2026 | 6,122.0 thousands | — |
| December 2025 | 6,129.0 thousands | — |
| November 2025 | 6,175.0 thousands | — |
| September 2025 | 6,120.0 thousands | 4.4 |
| August 2025 | 6,215.0 thousands | 3.9 |
| July 2025 | 6,158.0 thousands | 3.1 |
| June 2025 | 6,147.0 thousands | 2.8 |
| May 2025 | 6,178.0 thousands | 3.8 |
| April 2025 | 6,266.0 thousands | 3.2 |
| March 2025 | 6,078.0 thousands | 0.3 |
| February 2025 | 6,012.0 thousands | 1.5 |
| January 2025 | 5,914.0 thousands | −0.3 |
| December 2024 | 5,816.0 thousands | −3.3 |
| November 2024 | 5,835.0 thousands | −4.5 |
| October 2024 | 5,870.0 thousands | −2.7 |
| September 2024 | 5,863.0 thousands | 0.6 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-45880.EMP.M.NSA"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-45880.EMP.M.NSA",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```