# Employment: Gardnerville Ranchos, NV-CA Micropolitan Statistical Area (U)

Employment: Gardnerville Ranchos, NV-CA Micropolitan Statistical Area (U) was up 4.4% year on year in September 2025, compared with 4.0% in August 2025.
The level stood at 23,668 thousands.
That is the highest reading since December 2022.
Over the past ten years it has ranged from −27.9% (May 2020) to 33.9% (Apr 2021), averaging 1.2%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-23820.EMP.M.NSA`
- Frequency: monthly
- Units: thousands
- Coverage: 1990-01-01 to 2026-09-01 (440 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/employment-gardnerville-ranchos-nv-ca-micropolitan-statistical-area-u

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 23,668 thousands | — |
| August 2026 | 23,950 thousands | — |
| July 2026 | 24,399 thousands | — |
| June 2026 | 24,174 thousands | — |
| May 2026 | 23,907 thousands | — |
| April 2026 | 23,905 thousands | — |
| March 2026 | 24,287 thousands | — |
| February 2026 | 24,106 thousands | — |
| January 2026 | 24,388 thousands | — |
| December 2025 | 24,445 thousands | — |
| November 2025 | 24,255 thousands | — |
| September 2025 | 23,914 thousands | 4.4 |
| August 2025 | 23,845 thousands | 4.0 |
| July 2025 | 24,067 thousands | 4.1 |
| June 2025 | 23,910 thousands | 4.1 |
| May 2025 | 23,227 thousands | 3.5 |
| April 2025 | 23,210 thousands | 2.5 |
| March 2025 | 23,271 thousands | 2.9 |
| February 2025 | 23,276 thousands | 3.4 |
| January 2025 | 23,139 thousands | 4.0 |
| December 2024 | 22,942 thousands | 4.0 |
| November 2024 | 22,608 thousands | 4.0 |
| October 2024 | 22,596 thousands | 3.6 |
| September 2024 | 22,905 thousands | 3.5 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-23820.EMP.M.NSA"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-23820.EMP.M.NSA",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```