# Average Weekly Earnings: Total Private — Logan, UT-ID (NSA)

Average Weekly Earnings: Total Private — Logan, UT-ID (NSA) was down 4.3% year on year in September 2026, compared with −1.2% in August 2026.
The level stood at 964.1 USD/week.
That is the lowest reading since November 2024.
Over the past ten years it has ranged from −17.3% (Apr 2024) to 17.2% (Feb 2018), averaging 3.8%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-30860.AWE.M.NSA.IND-05000000`
- Frequency: monthly
- Units: USD/week
- Coverage: 2007-01-01 to 2026-09-01 (237 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/average-weekly-earnings-total-private-logan-ut-id-nsa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 964.1 USD/week | −4.3 |
| August 2026 | 1,010.8 USD/week | −1.2 |
| July 2026 | 990.6 USD/week | −1.8 |
| June 2026 | 1,005.7 USD/week | −2.6 |
| May 2026 | 988.1 USD/week | −1.8 |
| April 2026 | 974.8 USD/week | −1.1 |
| March 2026 | 957.8 USD/week | −4.2 |
| February 2026 | 967.2 USD/week | −2.3 |
| January 2026 | 956.7 USD/week | 2.6 |
| December 2025 | 946.3 USD/week | −0.9 |
| November 2025 | 1,008.3 USD/week | 8.2 |
| October 2025 | 982.6 USD/week | 7.1 |
| September 2025 | 1,007.7 USD/week | 5.6 |
| August 2025 | 1,023.0 USD/week | 11.5 |
| July 2025 | 1,008.7 USD/week | 10.3 |
| June 2025 | 1,032.6 USD/week | 8.2 |
| May 2025 | 1,006.1 USD/week | 5.9 |
| April 2025 | 985.9 USD/week | 10.0 |
| March 2025 | 999.6 USD/week | 9.4 |
| February 2025 | 990.2 USD/week | 5.3 |
| January 2025 | 932.6 USD/week | −3.1 |
| December 2024 | 955.2 USD/week | −3.8 |
| November 2024 | 931.6 USD/week | −8.0 |
| October 2024 | 917.7 USD/week | −10.5 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-30860.AWE.M.NSA.IND-05000000"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-30860.AWE.M.NSA.IND-05000000",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```