# Average Weekly Earnings: Private Service Providing — UT (statewide) (NSA)

Average Weekly Earnings: Private Service Providing — UT (statewide) (NSA) was up 1.7% year on year in September 2026, compared with 2.9% in August 2026.
The level stood at 1,136.2 USD/week.
Over the past ten years it has ranged from −2.5% (Jan 2018) to 11.3% (Mar 2020), averaging 3.4%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-UT.AWE.M.NSA.IND-08000000`
- Frequency: monthly
- Units: USD/week
- Coverage: 2007-01-01 to 2026-09-01 (237 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/average-weekly-earnings-private-service-providing-ut-statewide-nsa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 1,136.2 USD/week | 1.7 |
| August 2026 | 1,157.0 USD/week | 2.9 |
| July 2026 | 1,127.3 USD/week | 0.8 |
| June 2026 | 1,128.0 USD/week | −1.0 |
| May 2026 | 1,132.6 USD/week | 3.0 |
| April 2026 | 1,126.6 USD/week | 2.6 |
| March 2026 | 1,164.0 USD/week | 3.2 |
| February 2026 | 1,167.2 USD/week | 3.9 |
| January 2026 | 1,126.6 USD/week | 7.1 |
| December 2025 | 1,127.9 USD/week | 3.9 |
| November 2025 | 1,169.3 USD/week | 11.3 |
| October 2025 | 1,127.7 USD/week | 6.8 |
| September 2025 | 1,117.0 USD/week | 2.6 |
| August 2025 | 1,124.4 USD/week | 6.3 |
| July 2025 | 1,118.5 USD/week | 6.8 |
| June 2025 | 1,139.2 USD/week | 4.7 |
| May 2025 | 1,099.2 USD/week | 4.9 |
| April 2025 | 1,098.4 USD/week | 5.2 |
| March 2025 | 1,127.9 USD/week | 8.5 |
| February 2025 | 1,122.9 USD/week | 7.4 |
| January 2025 | 1,051.8 USD/week | 0.2 |
| December 2024 | 1,085.3 USD/week | 3.6 |
| November 2024 | 1,050.9 USD/week | 1.0 |
| October 2024 | 1,055.8 USD/week | −1.4 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-UT.AWE.M.NSA.IND-08000000"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-UT.AWE.M.NSA.IND-08000000",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```