# Average Weekly Earnings: Private Service Providing — RI (statewide) (NSA)

Average Weekly Earnings: Private Service Providing — RI (statewide) (NSA) was up 3.9% year on year in September 2026, compared with 3.4% in August 2026.
The level stood at 1,216.1 USD/week.
Over the past ten years it has ranged from −3.7% (Jul 2019) to 10.5% (Jan 2023), averaging 3.9%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-RI.AWE.M.NSA.IND-08000000`
- Frequency: monthly
- Units: USD/week
- Coverage: 2007-01-01 to 2026-09-01 (237 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/average-weekly-earnings-private-service-providing-ri-statewide-nsa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 1,216.1 USD/week | 3.9 |
| August 2026 | 1,216.5 USD/week | 3.4 |
| July 2026 | 1,211.5 USD/week | 2.9 |
| June 2026 | 1,193.2 USD/week | 0.9 |
| May 2026 | 1,194.0 USD/week | 2.5 |
| April 2026 | 1,196.2 USD/week | 2.9 |
| March 2026 | 1,218.6 USD/week | 5.1 |
| February 2026 | 1,219.1 USD/week | 5.6 |
| January 2026 | 1,199.1 USD/week | 4.5 |
| December 2025 | 1,212.8 USD/week | 3.0 |
| November 2025 | 1,190.6 USD/week | 3.1 |
| October 2025 | 1,181.1 USD/week | 2.5 |
| September 2025 | 1,171.0 USD/week | −0.4 |
| August 2025 | 1,176.2 USD/week | 1.2 |
| July 2025 | 1,176.9 USD/week | 2.8 |
| June 2025 | 1,182.4 USD/week | 2.7 |
| May 2025 | 1,165.1 USD/week | 1.7 |
| April 2025 | 1,162.2 USD/week | 1.7 |
| March 2025 | 1,159.0 USD/week | 1.1 |
| February 2025 | 1,154.6 USD/week | 0.5 |
| January 2025 | 1,147.6 USD/week | 0.8 |
| December 2024 | 1,177.2 USD/week | 2.4 |
| November 2024 | 1,154.7 USD/week | 0.5 |
| October 2024 | 1,152.8 USD/week | −0.00 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-RI.AWE.M.NSA.IND-08000000"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-RI.AWE.M.NSA.IND-08000000",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```