# Average Weekly Earnings: Private Service Providing — PA (statewide) (NSA)

Average Weekly Earnings: Private Service Providing — PA (statewide) (NSA) was up 3.5% year on year in September 2026, compared with 4.8% in August 2026.
The level stood at 1,119.9 USD/week.
Over the past ten years it has ranged from −0.6% (Jul 2019) to 8.9% (May 2020), averaging 3.3%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-PA.AWE.M.NSA.IND-08000000`
- Frequency: monthly
- Units: USD/week
- Coverage: 2007-01-01 to 2026-09-01 (237 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/average-weekly-earnings-private-service-providing-pa-statewide-nsa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 1,119.9 USD/week | 3.5 |
| August 2026 | 1,114.5 USD/week | 4.8 |
| July 2026 | 1,095.2 USD/week | 3.1 |
| June 2026 | 1,083.4 USD/week | 1.9 |
| May 2026 | 1,084.0 USD/week | 2.5 |
| April 2026 | 1,090.2 USD/week | 2.4 |
| March 2026 | 1,102.2 USD/week | 3.5 |
| February 2026 | 1,106.5 USD/week | 4.6 |
| January 2026 | 1,087.6 USD/week | 3.9 |
| December 2025 | 1,088.2 USD/week | 2.9 |
| November 2025 | 1,098.0 USD/week | 4.8 |
| October 2025 | 1,081.8 USD/week | 3.8 |
| September 2025 | 1,082.4 USD/week | 2.8 |
| August 2025 | 1,063.6 USD/week | 3.1 |
| July 2025 | 1,061.9 USD/week | 3.6 |
| June 2025 | 1,063.6 USD/week | 3.3 |
| May 2025 | 1,057.5 USD/week | 3.1 |
| April 2025 | 1,064.7 USD/week | 3.3 |
| March 2025 | 1,065.4 USD/week | 4.3 |
| February 2025 | 1,058.0 USD/week | 4.0 |
| January 2025 | 1,047.0 USD/week | 3.0 |
| December 2024 | 1,057.3 USD/week | 3.9 |
| November 2024 | 1,047.5 USD/week | 4.4 |
| October 2024 | 1,042.5 USD/week | 2.6 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-PA.AWE.M.NSA.IND-08000000"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-PA.AWE.M.NSA.IND-08000000",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```