# Average Weekly Earnings: Private Service Providing — MT (statewide) (NSA)

Average Weekly Earnings: Private Service Providing — MT (statewide) (NSA) was up 1.8% year on year in September 2026, compared with 3.4% in August 2026.
The level stood at 1,068.3 USD/week.
Over the past ten years it has ranged from −0.9% (Jun 2026) to 12.8% (Aug 2023), averaging 4.6%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-MT.AWE.M.NSA.IND-08000000`
- Frequency: monthly
- Units: USD/week
- Coverage: 2007-01-01 to 2026-09-01 (237 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/average-weekly-earnings-private-service-providing-mt-statewide-nsa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 1,068.3 USD/week | 1.8 |
| August 2026 | 1,086.0 USD/week | 3.4 |
| July 2026 | 1,067.3 USD/week | 0.6 |
| June 2026 | 1,043.9 USD/week | −0.9 |
| May 2026 | 1,053.3 USD/week | −0.09 |
| April 2026 | 1,064.6 USD/week | 0.8 |
| March 2026 | 1,063.7 USD/week | 0.4 |
| February 2026 | 1,079.2 USD/week | 1.2 |
| January 2026 | 1,069.2 USD/week | 4.1 |
| December 2025 | 1,054.6 USD/week | 2.3 |
| November 2025 | 1,089.0 USD/week | 5.6 |
| October 2025 | 1,055.9 USD/week | 2.0 |
| September 2025 | 1,049.4 USD/week | 1.1 |
| August 2025 | 1,050.4 USD/week | 2.9 |
| July 2025 | 1,060.9 USD/week | 5.8 |
| June 2025 | 1,053.4 USD/week | 4.8 |
| May 2025 | 1,054.3 USD/week | 5.0 |
| April 2025 | 1,056.6 USD/week | 7.7 |
| March 2025 | 1,059.5 USD/week | 8.9 |
| February 2025 | 1,066.7 USD/week | 7.8 |
| January 2025 | 1,026.8 USD/week | 4.4 |
| December 2024 | 1,030.4 USD/week | 6.9 |
| November 2024 | 1,031.4 USD/week | 5.3 |
| October 2024 | 1,035.5 USD/week | 2.3 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-MT.AWE.M.NSA.IND-08000000"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-MT.AWE.M.NSA.IND-08000000",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```