# Average Weekly Earnings: Private Service Providing — IL (statewide) (NSA)

Average Weekly Earnings: Private Service Providing — IL (statewide) (NSA) was up 3.2% year on year in September 2026, compared with 5.5% in August 2026.
The level stood at 1,163.5 USD/week.
Over the past ten years it has ranged from −3.2% (May 2023) to 10.6% (Nov 2020), averaging 3.0%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-IL.AWE.M.NSA.IND-08000000`
- Frequency: monthly
- Units: USD/week
- Coverage: 2007-01-01 to 2026-09-01 (237 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/average-weekly-earnings-private-service-providing-il-statewide-nsa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 1,163.5 USD/week | 3.2 |
| August 2026 | 1,188.6 USD/week | 5.5 |
| July 2026 | 1,154.4 USD/week | 3.6 |
| June 2026 | 1,145.6 USD/week | 0.9 |
| May 2026 | 1,145.6 USD/week | 2.9 |
| April 2026 | 1,146.6 USD/week | 3.8 |
| March 2026 | 1,167.7 USD/week | 3.3 |
| February 2026 | 1,189.0 USD/week | 4.3 |
| January 2026 | 1,149.8 USD/week | 4.6 |
| December 2025 | 1,144.3 USD/week | 2.0 |
| November 2025 | 1,169.6 USD/week | 8.1 |
| October 2025 | 1,134.2 USD/week | 5.0 |
| September 2025 | 1,127.1 USD/week | 2.9 |
| August 2025 | 1,127.0 USD/week | 5.0 |
| July 2025 | 1,114.1 USD/week | 4.9 |
| June 2025 | 1,135.2 USD/week | 4.9 |
| May 2025 | 1,113.6 USD/week | 5.9 |
| April 2025 | 1,105.2 USD/week | 4.8 |
| March 2025 | 1,130.3 USD/week | 6.7 |
| February 2025 | 1,140.3 USD/week | 7.0 |
| January 2025 | 1,099.8 USD/week | 3.7 |
| December 2024 | 1,121.7 USD/week | 4.3 |
| November 2024 | 1,082.2 USD/week | 1.5 |
| October 2024 | 1,080.6 USD/week | −1.3 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-IL.AWE.M.NSA.IND-08000000"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-IL.AWE.M.NSA.IND-08000000",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```