# Average Weekly Earnings: Private Service Providing — CO (statewide) (NSA)

Average Weekly Earnings: Private Service Providing — CO (statewide) (NSA) was up 3.9% year on year in September 2026, compared with 7.1% in August 2026.
The level stood at 1,292.6 USD/week.
Over the past ten years it has ranged from −3.7% (Nov 2016) to 11.3% (Jan 2022), averaging 4.0%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-CO.AWE.M.NSA.IND-08000000`
- Frequency: monthly
- Units: USD/week
- Coverage: 2007-01-01 to 2026-09-01 (237 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/average-weekly-earnings-private-service-providing-co-statewide-nsa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 1,292.6 USD/week | 3.9 |
| August 2026 | 1,334.3 USD/week | 7.1 |
| July 2026 | 1,267.2 USD/week | 2.9 |
| June 2026 | 1,261.7 USD/week | 0.07 |
| May 2026 | 1,262.9 USD/week | 3.1 |
| April 2026 | 1,246.6 USD/week | 1.6 |
| March 2026 | 1,266.2 USD/week | 1.1 |
| February 2026 | 1,265.2 USD/week | −0.3 |
| January 2026 | 1,263.5 USD/week | 1.9 |
| December 2025 | 1,256.0 USD/week | −1.5 |
| November 2025 | 1,299.2 USD/week | 5.5 |
| October 2025 | 1,257.7 USD/week | 2.1 |
| September 2025 | 1,243.6 USD/week | −0.4 |
| August 2025 | 1,246.0 USD/week | 3.8 |
| July 2025 | 1,231.5 USD/week | 1.5 |
| June 2025 | 1,260.7 USD/week | 1.7 |
| May 2025 | 1,225.3 USD/week | 1.3 |
| April 2025 | 1,226.5 USD/week | 2.0 |
| March 2025 | 1,252.5 USD/week | 5.6 |
| February 2025 | 1,268.5 USD/week | 7.3 |
| January 2025 | 1,239.5 USD/week | 5.8 |
| December 2024 | 1,274.7 USD/week | 8.5 |
| November 2024 | 1,231.7 USD/week | 5.3 |
| October 2024 | 1,231.7 USD/week | 3.8 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-CO.AWE.M.NSA.IND-08000000"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-CO.AWE.M.NSA.IND-08000000",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```