# United States Average weekly earnings of all employees, traveler accommodation, not seasonally adjusted

United States Average weekly earnings of all employees, traveler accommodation, not seasonally adjusted was up 4.0% year on year in September 2026, compared with 4.5% in August 2026.
The level stood at 788.0 USD/week.
Over the past ten years it has ranged from −9.0% (Jun 2020) to 31.7% (Dec 2021), averaging 4.5%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US.AWE.M.NSA.IND-70721100`
- Frequency: monthly
- Units: USD/week
- Coverage: 2006-03-01 to 2026-09-01 (247 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/average-weekly-earnings-of-all-employees-traveler-accommodation-not

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 788.0 USD/week | 4.0 |
| August 2026 | 785.9 USD/week | 4.5 |
| July 2026 | 782.5 USD/week | 3.6 |
| June 2026 | 777.8 USD/week | 3.3 |
| May 2026 | 781.9 USD/week | 5.6 |
| April 2026 | 782.3 USD/week | 2.8 |
| March 2026 | 777.6 USD/week | 2.6 |
| February 2026 | 781.4 USD/week | 3.9 |
| January 2026 | 761.9 USD/week | 5.3 |
| December 2025 | 758.1 USD/week | 2.3 |
| November 2025 | 765.9 USD/week | 4.4 |
| October 2025 | 770.7 USD/week | 4.8 |
| September 2025 | 757.7 USD/week | 2.2 |
| August 2025 | 752.4 USD/week | 3.6 |
| July 2025 | 755.0 USD/week | 2.9 |
| June 2025 | 752.9 USD/week | 2.3 |
| May 2025 | 740.2 USD/week | 2.1 |
| April 2025 | 761.4 USD/week | 4.4 |
| March 2025 | 757.7 USD/week | 4.1 |
| February 2025 | 751.8 USD/week | 4.3 |
| January 2025 | 723.5 USD/week | 1.6 |
| December 2024 | 741.1 USD/week | 3.8 |
| November 2024 | 733.9 USD/week | 2.4 |
| October 2024 | 735.5 USD/week | 0.6 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US.AWE.M.NSA.IND-70721100"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US.AWE.M.NSA.IND-70721100",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```