# United States Average weekly earnings of all employees, limited-service restaurants, seasonally adjusted

United States Average weekly earnings of all employees, limited-service restaurants, seasonally adjusted was up 3.5% year on year in September 2026, compared with 2.4% in August 2026.
The level stood at 491.2 USD/week.
Over the past ten years it has ranged from 0.4% (Apr 2020) to 15.8% (Apr 2021), averaging 5.4%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US.AWE.M.SA.IND-70722513`
- Frequency: monthly
- Units: USD/week
- Coverage: 2006-03-01 to 2026-09-01 (247 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/average-weekly-earnings-of-all-employees-limited-service-restaurants

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 491.2 USD/week | 3.5 |
| August 2026 | 485.9 USD/week | 2.4 |
| July 2026 | 487.9 USD/week | 3.6 |
| June 2026 | 486.0 USD/week | 3.6 |
| May 2026 | 486.7 USD/week | 3.7 |
| April 2026 | 485.4 USD/week | 3.9 |
| March 2026 | 483.4 USD/week | 3.8 |
| February 2026 | 484.0 USD/week | 4.6 |
| January 2026 | 479.4 USD/week | 5.5 |
| December 2025 | 482.2 USD/week | 5.1 |
| November 2025 | 479.8 USD/week | 4.9 |
| October 2025 | 476.6 USD/week | 4.2 |
| September 2025 | 474.6 USD/week | 5.6 |
| August 2025 | 474.6 USD/week | 6.6 |
| July 2025 | 471.0 USD/week | 6.1 |
| June 2025 | 469.2 USD/week | 5.8 |
| May 2025 | 469.3 USD/week | 6.4 |
| April 2025 | 467.0 USD/week | 6.4 |
| March 2025 | 465.7 USD/week | 6.8 |
| February 2025 | 462.6 USD/week | 5.7 |
| January 2025 | 454.5 USD/week | 4.9 |
| December 2024 | 459.0 USD/week | 6.2 |
| November 2024 | 457.2 USD/week | 6.5 |
| October 2024 | 457.5 USD/week | 6.7 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US.AWE.M.SA.IND-70722513"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US.AWE.M.SA.IND-70722513",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```