# Average Hourly Earnings: Total Private — Waterloo-Cedar Falls, IA (NSA)

Average Hourly Earnings: Total Private — Waterloo-Cedar Falls, IA (NSA) was up 2.3% year on year in September 2026, compared with 2.8% in August 2026.
The level stood at 31.86 USD/hour.
That is the lowest reading since July 2024.
Over the past ten years it has ranged from −2.9% (Feb 2017) to 12.1% (Aug 2025), averaging 3.4%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-47940.AHE.M.NSA.IND-05000000`
- Frequency: monthly
- Units: USD/hour
- Coverage: 2007-01-01 to 2026-09-01 (237 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/average-hourly-earnings-total-private-waterloo-cedar-falls-ia-nsa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 31.86 USD/hour | 2.3 |
| August 2026 | 31.74 USD/hour | 2.8 |
| July 2026 | 31.23 USD/hour | 2.7 |
| June 2026 | 30.50 USD/hour | 2.6 |
| May 2026 | 31.45 USD/hour | 2.9 |
| April 2026 | 31.10 USD/hour | 3.0 |
| March 2026 | 31.17 USD/hour | 2.5 |
| February 2026 | 31.26 USD/hour | 6.9 |
| January 2026 | 31.03 USD/hour | 7.1 |
| December 2025 | 30.90 USD/hour | 9.2 |
| November 2025 | 31.23 USD/hour | 9.8 |
| October 2025 | 31.42 USD/hour | 9.4 |
| September 2025 | 31.15 USD/hour | 9.0 |
| August 2025 | 30.88 USD/hour | 12.1 |
| July 2025 | 30.40 USD/hour | 11.2 |
| June 2025 | 29.72 USD/hour | 10.4 |
| May 2025 | 30.57 USD/hour | 12.0 |
| April 2025 | 30.19 USD/hour | 9.8 |
| March 2025 | 30.41 USD/hour | 11.8 |
| February 2025 | 29.25 USD/hour | 5.5 |
| January 2025 | 28.98 USD/hour | 3.8 |
| December 2024 | 28.29 USD/hour | 3.4 |
| November 2024 | 28.43 USD/hour | 3.7 |
| October 2024 | 28.72 USD/hour | 6.2 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-47940.AHE.M.NSA.IND-05000000"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-47940.AHE.M.NSA.IND-05000000",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```