# Average Hourly Earnings: Total Private — Seattle-Bellevue-Kent, WA Metropolitan Division (NSA)

Average Hourly Earnings: Total Private — Seattle-Bellevue-Kent, WA Metropolitan Division (NSA) was up 5.1% year on year in September 2026, compared with 6.1% in August 2026.
The level stood at 50.24 USD/hour.
Over the past ten years it has ranged from −6.1% (Apr 2021) to 11.2% (Mar 2025), averaging 3.3%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-42644.AHE.M.NSA.IND-05000000`
- Frequency: monthly
- Units: USD/hour
- Coverage: 2007-01-01 to 2026-09-01 (237 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/average-hourly-earnings-total-private-seattle-bellevue-kent-wa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 50.24 USD/hour | 5.1 |
| August 2026 | 50.31 USD/hour | 6.1 |
| July 2026 | 49.61 USD/hour | 5.8 |
| June 2026 | 49.34 USD/hour | 4.0 |
| May 2026 | 50.22 USD/hour | 6.9 |
| April 2026 | 49.70 USD/hour | 7.0 |
| March 2026 | 49.77 USD/hour | 7.3 |
| February 2026 | 49.70 USD/hour | 6.4 |
| January 2026 | 50.10 USD/hour | 9.4 |
| December 2025 | 49.07 USD/hour | 7.1 |
| November 2025 | 49.56 USD/hour | 10.1 |
| October 2025 | 48.52 USD/hour | 9.4 |
| September 2025 | 47.78 USD/hour | 8.6 |
| August 2025 | 47.40 USD/hour | 9.7 |
| July 2025 | 46.90 USD/hour | 9.3 |
| June 2025 | 47.43 USD/hour | 10.0 |
| May 2025 | 46.97 USD/hour | 10.8 |
| April 2025 | 46.47 USD/hour | 10.0 |
| March 2025 | 46.37 USD/hour | 11.2 |
| February 2025 | 46.69 USD/hour | 11.0 |
| January 2025 | 45.78 USD/hour | 9.1 |
| December 2024 | 45.80 USD/hour | 6.0 |
| November 2024 | 45.02 USD/hour | 5.3 |
| October 2024 | 44.37 USD/hour | 2.4 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-42644.AHE.M.NSA.IND-05000000"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-42644.AHE.M.NSA.IND-05000000",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```