# United States Average hourly earnings of all employees, utility system construction, seasonally adjusted

United States Average hourly earnings of all employees, utility system construction, seasonally adjusted was up 4.6% year on year in September 2026, compared with 4.5% in August 2026.
The level stood at 43.54 USD/hour.
Over the past ten years it has ranged from −2.0% (Dec 2020) to 9.8% (Jan 2024), averaging 4.0%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US.AHE.M.SA.IND-20237100`
- Frequency: monthly
- Units: USD/hour
- Coverage: 2006-03-01 to 2026-09-01 (247 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/average-hourly-earnings-of-all-employees-utility-system-construction

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 43.54 USD/hour | 4.6 |
| August 2026 | 43.50 USD/hour | 4.5 |
| July 2026 | 43.31 USD/hour | 5.1 |
| June 2026 | 43.28 USD/hour | 4.8 |
| May 2026 | 43.24 USD/hour | 5.4 |
| April 2026 | 42.82 USD/hour | 4.0 |
| March 2026 | 42.96 USD/hour | 4.3 |
| February 2026 | 42.59 USD/hour | 3.6 |
| January 2026 | 42.46 USD/hour | 3.4 |
| December 2025 | 42.32 USD/hour | 4.0 |
| November 2025 | 42.10 USD/hour | 3.9 |
| October 2025 | 42.16 USD/hour | 4.1 |
| September 2025 | 41.62 USD/hour | 3.5 |
| August 2025 | 41.63 USD/hour | 4.2 |
| July 2025 | 41.20 USD/hour | 2.9 |
| June 2025 | 41.30 USD/hour | 4.7 |
| May 2025 | 41.02 USD/hour | 4.2 |
| April 2025 | 41.19 USD/hour | 4.1 |
| March 2025 | 41.17 USD/hour | 6.0 |
| February 2025 | 41.10 USD/hour | 6.7 |
| January 2025 | 41.06 USD/hour | 4.7 |
| December 2024 | 40.70 USD/hour | 5.3 |
| November 2024 | 40.51 USD/hour | 5.4 |
| October 2024 | 40.50 USD/hour | 6.2 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US.AHE.M.SA.IND-20237100"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US.AHE.M.SA.IND-20237100",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```