# United States Average hourly earnings of all employees, residential remodelers, not seasonally adjusted

United States Average hourly earnings of all employees, residential remodelers, not seasonally adjusted was up 2.1% year on year in September 2026, compared with 0.8% in August 2026.
The level stood at 38.61 USD/hour.
Over the past ten years it has ranged from −1.9% (Jul 2019) to 9.3% (May 2022), averaging 4.2%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US.AHE.M.NSA.IND-20236118`
- Frequency: monthly
- Units: USD/hour
- Coverage: 2006-03-01 to 2026-09-01 (247 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/average-hourly-earnings-of-all-employees-residential-remodelers-not

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 38.61 USD/hour | 2.1 |
| August 2026 | 38.39 USD/hour | 0.8 |
| July 2026 | 38.14 USD/hour | 1.4 |
| June 2026 | 37.85 USD/hour | 1.8 |
| May 2026 | 38.12 USD/hour | 3.6 |
| April 2026 | 37.98 USD/hour | 2.5 |
| March 2026 | 37.36 USD/hour | 2.9 |
| February 2026 | 37.55 USD/hour | 3.0 |
| January 2026 | 37.31 USD/hour | 2.8 |
| December 2025 | 37.68 USD/hour | 3.2 |
| November 2025 | 37.39 USD/hour | 2.0 |
| October 2025 | 37.87 USD/hour | 4.5 |
| September 2025 | 37.82 USD/hour | 4.6 |
| August 2025 | 38.07 USD/hour | 5.3 |
| July 2025 | 37.62 USD/hour | 4.8 |
| June 2025 | 37.19 USD/hour | 4.6 |
| May 2025 | 36.80 USD/hour | 3.6 |
| April 2025 | 37.04 USD/hour | 4.3 |
| March 2025 | 36.31 USD/hour | 3.8 |
| February 2025 | 36.46 USD/hour | 5.1 |
| January 2025 | 36.28 USD/hour | 5.9 |
| December 2024 | 36.50 USD/hour | 6.5 |
| November 2024 | 36.64 USD/hour | 8.2 |
| October 2024 | 36.24 USD/hour | 6.8 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US.AHE.M.NSA.IND-20236118"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US.AHE.M.NSA.IND-20236118",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```