# United States Average hourly earnings of all employees, architectural services, not seasonally adjusted

United States Average hourly earnings of all employees, architectural services, not seasonally adjusted was up 2.9% year on year in September 2026, compared with 4.2% in August 2026.
The level stood at 50.95 USD/hour.
Over the past ten years it has ranged from −2.5% (Sep 2020) to 6.8% (Oct 2021), averaging 3.2%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US.AHE.M.NSA.IND-60541310`
- Frequency: monthly
- Units: USD/hour
- Coverage: 2006-03-01 to 2026-09-01 (247 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/average-hourly-earnings-of-all-employees-architectural-services-not

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 50.95 USD/hour | 2.9 |
| August 2026 | 50.86 USD/hour | 4.2 |
| July 2026 | 50.39 USD/hour | 4.0 |
| June 2026 | 50.55 USD/hour | 3.6 |
| May 2026 | 50.75 USD/hour | 3.7 |
| April 2026 | 50.59 USD/hour | 3.3 |
| March 2026 | 50.40 USD/hour | 2.2 |
| February 2026 | 50.35 USD/hour | 2.5 |
| January 2026 | 50.32 USD/hour | 4.0 |
| December 2025 | 49.38 USD/hour | 1.9 |
| November 2025 | 49.73 USD/hour | 4.4 |
| October 2025 | 49.05 USD/hour | 3.7 |
| September 2025 | 49.53 USD/hour | 2.7 |
| August 2025 | 48.83 USD/hour | 3.6 |
| July 2025 | 48.43 USD/hour | 2.7 |
| June 2025 | 48.80 USD/hour | 2.2 |
| May 2025 | 48.95 USD/hour | 3.0 |
| April 2025 | 48.98 USD/hour | 3.6 |
| March 2025 | 49.33 USD/hour | 6.0 |
| February 2025 | 49.10 USD/hour | 5.0 |
| January 2025 | 48.40 USD/hour | 3.0 |
| December 2024 | 48.45 USD/hour | 3.9 |
| November 2024 | 47.63 USD/hour | 1.8 |
| October 2024 | 47.31 USD/hour | −0.3 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US.AHE.M.NSA.IND-60541310"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US.AHE.M.NSA.IND-60541310",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```