# All Employees: Total Nonfarm — Pocatello, ID (NSA)

All Employees: Total Nonfarm — Pocatello, ID (NSA) was up 0.7% year on year in September 2026, compared with −1.2% in August 2026.
The level stood at 40.90 thousands.
That is the highest reading since August 2025.
Over the past ten years it has ranged from −8.8% (Apr 2020) to 9.1% (Apr 2021), averaging 1.2%.
The next update is expected on 23 November 2026.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-38540.PAYEMS.M.NSA`
- Frequency: monthly
- Units: thousands
- Coverage: 1990-01-01 to 2026-09-01 (441 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/all-employees-total-nonfarm-pocatello-id-nsa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 40.90 thousands | 0.7 |
| August 2026 | 40.10 thousands | −1.2 |
| July 2026 | 40.10 thousands | −0.5 |
| June 2026 | 40.40 thousands | −1.2 |
| May 2026 | 39.80 thousands | −2.7 |
| April 2026 | 40.40 thousands | −3.1 |
| March 2026 | 40.20 thousands | −2.0 |
| February 2026 | 39.70 thousands | −2.9 |
| January 2026 | 39.50 thousands | −2.7 |
| December 2025 | 40.40 thousands | −0.5 |
| November 2025 | 40.70 thousands | −0.5 |
| October 2025 | 40.70 thousands | −0.5 |
| September 2025 | 40.60 thousands | 0.2 |
| August 2025 | 40.60 thousands | 2.5 |
| July 2025 | 40.30 thousands | 2.0 |
| June 2025 | 40.90 thousands | 0.0 |
| May 2025 | 40.90 thousands | 1.7 |
| April 2025 | 41.70 thousands | 2.0 |
| March 2025 | 41.00 thousands | 2.2 |
| February 2025 | 40.90 thousands | 2.0 |
| January 2025 | 40.60 thousands | 2.0 |
| December 2024 | 40.60 thousands | 1.0 |
| November 2024 | 40.90 thousands | 1.2 |
| October 2024 | 40.90 thousands | 2.0 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-38540.PAYEMS.M.NSA"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-38540.PAYEMS.M.NSA",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```