# All Employees: Total Nonfarm — Chicago-Naperville-Elgin, IL-IN (NSA)

All Employees: Total Nonfarm — Chicago-Naperville-Elgin, IL-IN (NSA) was down 0.08% year on year in September 2026, compared with 0.1% in August 2026.
The level stood at 4,768.5 thousands.
Over the past ten years it has ranged from −13.5% (May 2020) to 8.7% (Apr 2021), averaging 0.5%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-16980.PAYEMS.M.NSA`
- Frequency: monthly
- Units: thousands
- Coverage: 1990-01-01 to 2026-09-01 (441 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/all-employees-total-nonfarm-chicago-naperville-elgin-il-in-nsa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 4,768.5 thousands | −0.08 |
| August 2026 | 4,779.2 thousands | 0.1 |
| July 2026 | 4,809.7 thousands | 0.3 |
| June 2026 | 4,813.0 thousands | 0.1 |
| May 2026 | 4,776.4 thousands | −0.1 |
| April 2026 | 4,734.1 thousands | 0.04 |
| March 2026 | 4,689.9 thousands | −0.06 |
| February 2026 | 4,664.7 thousands | −0.1 |
| January 2026 | 4,666.4 thousands | 0.04 |
| December 2025 | 4,783.1 thousands | 0.2 |
| November 2025 | 4,782.9 thousands | −0.02 |
| October 2025 | 4,786.8 thousands | 0.3 |
| September 2025 | 4,772.3 thousands | 0.3 |
| August 2025 | 4,774.3 thousands | 0.5 |
| July 2025 | 4,794.5 thousands | 0.7 |
| June 2025 | 4,807.1 thousands | 0.6 |
| May 2025 | 4,781.5 thousands | 0.8 |
| April 2025 | 4,732.3 thousands | 0.8 |
| March 2025 | 4,692.5 thousands | 0.7 |
| February 2025 | 4,671.5 thousands | 1.0 |
| January 2025 | 4,664.5 thousands | 1.0 |
| December 2024 | 4,773.1 thousands | 0.7 |
| November 2024 | 4,783.8 thousands | 0.7 |
| October 2024 | 4,771.7 thousands | 0.7 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-16980.PAYEMS.M.NSA"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-16980.PAYEMS.M.NSA",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```