# All Employees: Total Nonfarm — Albuquerque, NM (SA)

All Employees: Total Nonfarm — Albuquerque, NM (SA) was down 0.3% year on year in September 2026, compared with −0.5% in August 2026.
The level stood at 418.7 thousands.
That is the highest reading since July 2025.
Over the past ten years it has ranged from −11.8% (Apr 2020) to 9.3% (Apr 2021), averaging 0.9%.
The next update is expected on 23 November 2026.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-10740.PAYEMS.M.SA`
- Frequency: monthly
- Units: thousands
- Coverage: 1990-01-01 to 2026-09-01 (441 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/all-employees-total-nonfarm-albuquerque-nm-sa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 418.7 thousands | −0.3 |
| August 2026 | 418.5 thousands | −0.5 |
| July 2026 | 418.4 thousands | −0.5 |
| June 2026 | 418.3 thousands | −0.5 |
| May 2026 | 418.5 thousands | −0.7 |
| April 2026 | 418.6 thousands | −0.7 |
| March 2026 | 416.9 thousands | −1.2 |
| February 2026 | 417.0 thousands | −1.3 |
| January 2026 | 417.0 thousands | −1.2 |
| December 2025 | 418.2 thousands | −0.8 |
| November 2025 | 417.8 thousands | −0.9 |
| October 2025 | 419.4 thousands | −0.5 |
| September 2025 | 419.9 thousands | −0.6 |
| August 2025 | 420.6 thousands | −0.4 |
| July 2025 | 420.3 thousands | 0.02 |
| June 2025 | 420.2 thousands | −0.4 |
| May 2025 | 421.5 thousands | 0.2 |
| April 2025 | 421.7 thousands | 0.4 |
| March 2025 | 422.0 thousands | 0.4 |
| February 2025 | 422.3 thousands | 0.6 |
| January 2025 | 422.2 thousands | 0.8 |
| December 2024 | 421.5 thousands | 0.4 |
| November 2024 | 421.5 thousands | 1.0 |
| October 2024 | 421.6 thousands | 1.2 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-10740.PAYEMS.M.SA"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-10740.PAYEMS.M.SA",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```