# All Employees: Service-Providing — Pensacola-Ferry Pass-Brent, FL (NSA)

All Employees: Service-Providing — Pensacola-Ferry Pass-Brent, FL (NSA) was up 0.3% year on year in September 2026, compared with 0.2% in August 2026.
The level stood at 182.8 thousands.
Over the past ten years it has ranged from −9.3% (Apr 2020) to 9.8% (Apr 2021), averaging 1.7%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-37860.PAYEMS.M.NSA.IND-07000000`
- Frequency: monthly
- Units: thousands
- Coverage: 1990-01-01 to 2026-09-01 (441 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/all-employees-service-providing-pensacola-ferry-pass-brent-fl-nsa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 182.8 thousands | 0.3 |
| August 2026 | 183.2 thousands | 0.2 |
| July 2026 | 182.2 thousands | 0.1 |
| June 2026 | 181.8 thousands | 0.2 |
| May 2026 | 183.6 thousands | −0.1 |
| April 2026 | 184.2 thousands | 0.5 |
| March 2026 | 182.8 thousands | 0.2 |
| February 2026 | 182.2 thousands | 0.7 |
| January 2026 | 181.6 thousands | 0.9 |
| December 2025 | 182.6 thousands | 1.3 |
| November 2025 | 183.1 thousands | 0.9 |
| October 2025 | 182.7 thousands | 1.1 |
| September 2025 | 182.2 thousands | 1.1 |
| August 2025 | 182.9 thousands | 0.9 |
| July 2025 | 182.0 thousands | 1.1 |
| June 2025 | 181.4 thousands | 0.9 |
| May 2025 | 183.8 thousands | 1.4 |
| April 2025 | 183.2 thousands | 0.8 |
| March 2025 | 182.4 thousands | 0.9 |
| February 2025 | 180.9 thousands | 0.9 |
| January 2025 | 180.0 thousands | 1.0 |
| December 2024 | 180.2 thousands | −0.06 |
| November 2024 | 181.4 thousands | −0.06 |
| October 2024 | 180.7 thousands | −0.2 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-37860.PAYEMS.M.NSA.IND-07000000"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-37860.PAYEMS.M.NSA.IND-07000000",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```