# All Employees: Service-Providing — Dayton-Kettering-Beavercreek, OH (NSA)

All Employees: Service-Providing — Dayton-Kettering-Beavercreek, OH (NSA) was up 0.7% year on year in September 2026, compared with 0.3% in August 2026.
The level stood at 343.8 thousands.
Over the past ten years it has ranged from −14.7% (Apr 2020) to 11.7% (Apr 2021), averaging 0.4%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-19430.PAYEMS.M.NSA.IND-07000000`
- Frequency: monthly
- Units: thousands
- Coverage: 1990-01-01 to 2026-09-01 (441 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/all-employees-service-providing-dayton-kettering-beavercreek-oh-nsa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 343.8 thousands | 0.7 |
| August 2026 | 344.1 thousands | 0.3 |
| July 2026 | 344.8 thousands | 0.7 |
| June 2026 | 344.5 thousands | 0.7 |
| May 2026 | 343.1 thousands | 0.06 |
| April 2026 | 341.1 thousands | −0.1 |
| March 2026 | 339.2 thousands | −0.1 |
| February 2026 | 338.0 thousands | −0.1 |
| January 2026 | 337.8 thousands | 0.3 |
| December 2025 | 342.8 thousands | −0.2 |
| November 2025 | 343.4 thousands | −0.06 |
| October 2025 | 341.9 thousands | −0.1 |
| September 2025 | 341.5 thousands | 0.3 |
| August 2025 | 342.9 thousands | 0.4 |
| July 2025 | 342.4 thousands | 0.4 |
| June 2025 | 342.0 thousands | 0.3 |
| May 2025 | 342.9 thousands | 0.6 |
| April 2025 | 341.5 thousands | 0.5 |
| March 2025 | 339.6 thousands | 0.5 |
| February 2025 | 338.4 thousands | 0.7 |
| January 2025 | 336.8 thousands | 0.7 |
| December 2024 | 343.5 thousands | 0.7 |
| November 2024 | 343.6 thousands | 0.9 |
| October 2024 | 342.4 thousands | 1.2 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-19430.PAYEMS.M.NSA.IND-07000000"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-19430.PAYEMS.M.NSA.IND-07000000",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```