# All Employees: Service-Providing — Bridgeport-Stamford-Danbury, CT (NSA)

All Employees: Service-Providing — Bridgeport-Stamford-Danbury, CT (NSA) was up 1.2% year on year in September 2026, compared with 1.5% in August 2026.
The level stood at 374.0 thousands.
Over the past ten years it has ranged from −20.0% (Apr 2020) to 16.6% (Apr 2021), averaging 0.2%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-14860.PAYEMS.M.NSA.IND-07000000`
- Frequency: monthly
- Units: thousands
- Coverage: 1990-01-01 to 2026-09-01 (441 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/all-employees-service-providing-bridgeport-stamford-danbury-ct-nsa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 374.0 thousands | 1.2 |
| August 2026 | 374.4 thousands | 1.5 |
| July 2026 | 377.9 thousands | 1.0 |
| June 2026 | 377.1 thousands | 0.6 |
| May 2026 | 372.0 thousands | 0.05 |
| April 2026 | 367.5 thousands | 0.08 |
| March 2026 | 363.4 thousands | −0.1 |
| February 2026 | 363.3 thousands | 0.5 |
| January 2026 | 365.2 thousands | 0.8 |
| December 2025 | 372.3 thousands | −0.2 |
| November 2025 | 372.1 thousands | −0.08 |
| October 2025 | 371.6 thousands | 0.4 |
| September 2025 | 369.4 thousands | 0.6 |
| August 2025 | 368.7 thousands | 0.8 |
| July 2025 | 374.3 thousands | 0.6 |
| June 2025 | 374.7 thousands | 0.2 |
| May 2025 | 371.8 thousands | 0.8 |
| April 2025 | 367.2 thousands | 0.6 |
| March 2025 | 363.9 thousands | 0.9 |
| February 2025 | 361.6 thousands | 1.0 |
| January 2025 | 362.2 thousands | 0.9 |
| December 2024 | 373.0 thousands | 1.1 |
| November 2024 | 372.4 thousands | 1.0 |
| October 2024 | 370.1 thousands | 1.0 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-14860.PAYEMS.M.NSA.IND-07000000"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-14860.PAYEMS.M.NSA.IND-07000000",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```