# All Employees: Mining, Logging and Construction — Florence-Muscle Shoals, AL (NSA)

All Employees: Mining, Logging and Construction — Florence-Muscle Shoals, AL (NSA) was up 0.0% year on year in September 2026, compared with 0.0% in August 2026.
The level stood at 4.20 thousands.
Over the past ten years it has ranged from −9.8% (Oct 2023) to 16.2% (Oct 2024), averaging 2.7%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-22520.PAYEMS.M.NSA.IND-15000000`
- Frequency: monthly
- Units: thousands
- Coverage: 1990-01-01 to 2026-09-01 (441 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/all-employees-mining-logging-and-construction-florence-muscle-shoals-al

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 4.20 thousands | 0.0 |
| August 2026 | 4.20 thousands | 0.0 |
| July 2026 | 4.20 thousands | 0.0 |
| June 2026 | 4.20 thousands | 2.4 |
| May 2026 | 4.20 thousands | 2.4 |
| April 2026 | 4.20 thousands | 2.4 |
| March 2026 | 4.20 thousands | 5.0 |
| February 2026 | 4.10 thousands | −2.4 |
| January 2026 | 4.10 thousands | −2.4 |
| December 2025 | 4.20 thousands | 0.0 |
| November 2025 | 4.20 thousands | 2.4 |
| October 2025 | 4.20 thousands | −2.3 |
| September 2025 | 4.20 thousands | −2.3 |
| August 2025 | 4.20 thousands | 0.0 |
| July 2025 | 4.20 thousands | 0.0 |
| June 2025 | 4.10 thousands | 2.5 |
| May 2025 | 4.10 thousands | 2.5 |
| April 2025 | 4.10 thousands | 2.5 |
| March 2025 | 4.00 thousands | 2.6 |
| February 2025 | 4.20 thousands | 10.5 |
| January 2025 | 4.20 thousands | 10.5 |
| December 2024 | 4.20 thousands | 13.5 |
| November 2024 | 4.10 thousands | 10.8 |
| October 2024 | 4.30 thousands | 16.2 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-22520.PAYEMS.M.NSA.IND-15000000"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-22520.PAYEMS.M.NSA.IND-15000000",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```