# All Employees: Local Government — RI (statewide) (SA)

All Employees: Local Government — RI (statewide) (SA) was down 0.3% year on year in September 2026, compared with −1.2% in August 2026.
The level stood at 32.90 thousands.
That is the highest reading since July 2025.
Over the past ten years it has ranged from −10.0% (Sep 2020) to 9.2% (Aug 2022), averaging −0.2%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-RI.PAYEMS.M.SA.IND-90930000`
- Frequency: monthly
- Units: thousands
- Coverage: 1990-01-01 to 2026-09-01 (441 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/all-employees-local-government-ri-statewide-sa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 32.90 thousands | −0.3 |
| August 2026 | 33.00 thousands | −1.2 |
| July 2026 | 33.00 thousands | −2.7 |
| June 2026 | 33.00 thousands | −1.5 |
| May 2026 | 32.90 thousands | −1.5 |
| April 2026 | 32.90 thousands | −1.5 |
| March 2026 | 33.00 thousands | −1.2 |
| February 2026 | 33.00 thousands | −0.9 |
| January 2026 | 32.90 thousands | −1.5 |
| December 2025 | 33.10 thousands | −0.9 |
| November 2025 | 33.00 thousands | −1.5 |
| October 2025 | 32.90 thousands | −1.5 |
| September 2025 | 33.00 thousands | −2.1 |
| August 2025 | 33.40 thousands | −0.9 |
| July 2025 | 33.90 thousands | 0.3 |
| June 2025 | 33.50 thousands | −0.9 |
| May 2025 | 33.40 thousands | −0.3 |
| April 2025 | 33.40 thousands | −0.9 |
| March 2025 | 33.40 thousands | −1.5 |
| February 2025 | 33.30 thousands | −1.5 |
| January 2025 | 33.40 thousands | −1.5 |
| December 2024 | 33.40 thousands | −1.5 |
| November 2024 | 33.50 thousands | −0.9 |
| October 2024 | 33.40 thousands | −1.5 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-RI.PAYEMS.M.SA.IND-90930000"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-RI.PAYEMS.M.SA.IND-90930000",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```