# All Employees: Leisure and Hospitality — Salt Lake City-Murray, UT (NSA)

All Employees: Leisure and Hospitality — Salt Lake City-Murray, UT (NSA) was up 1.6% year on year in September 2026, compared with 2.2% in August 2026.
The level stood at 71.80 thousands.
Over the past ten years it has ranged from −42.0% (Apr 2020) to 51.5% (Apr 2021), averaging 2.5%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-41620.PAYEMS.M.NSA.IND-70000000`
- Frequency: monthly
- Units: thousands
- Coverage: 1990-01-01 to 2026-09-01 (441 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/all-employees-leisure-and-hospitality-salt-lake-city-murray-ut-nsa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 71.80 thousands | 1.6 |
| August 2026 | 73.30 thousands | 2.2 |
| July 2026 | 73.70 thousands | 3.7 |
| June 2026 | 73.00 thousands | 1.5 |
| May 2026 | 71.70 thousands | 0.7 |
| April 2026 | 70.50 thousands | −2.6 |
| March 2026 | 69.40 thousands | −4.3 |
| February 2026 | 69.30 thousands | −2.9 |
| January 2026 | 68.10 thousands | −3.9 |
| December 2025 | 69.70 thousands | −3.1 |
| November 2025 | 69.40 thousands | −2.7 |
| October 2025 | 70.30 thousands | −1.1 |
| September 2025 | 70.70 thousands | −1.3 |
| August 2025 | 71.70 thousands | −0.1 |
| July 2025 | 71.10 thousands | 0.3 |
| June 2025 | 71.90 thousands | 1.6 |
| May 2025 | 71.20 thousands | 0.7 |
| April 2025 | 72.40 thousands | 2.3 |
| March 2025 | 72.50 thousands | 1.3 |
| February 2025 | 71.40 thousands | 1.0 |
| January 2025 | 70.90 thousands | 1.9 |
| December 2024 | 71.90 thousands | 2.7 |
| November 2024 | 71.30 thousands | 3.0 |
| October 2024 | 71.10 thousands | 2.4 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-41620.PAYEMS.M.NSA.IND-70000000"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-41620.PAYEMS.M.NSA.IND-70000000",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```