# All Employees: Government — Salt Lake City-Murray, UT (NSA)

All Employees: Government — Salt Lake City-Murray, UT (NSA) was up 1.8% year on year in September 2026, compared with 0.7% in August 2026.
The level stood at 123.2 thousands.
That is the highest reading since September 2025.
Over the past ten years it has ranged from −7.8% (May 2020) to 5.0% (Jan 2024), averaging 1.4%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-41620.PAYEMS.M.NSA.IND-90000000`
- Frequency: monthly
- Units: thousands
- Coverage: 1990-01-01 to 2026-09-01 (441 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/all-employees-government-salt-lake-city-murray-ut-nsa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 123.2 thousands | 1.8 |
| August 2026 | 120.9 thousands | 0.7 |
| July 2026 | 120.5 thousands | 1.6 |
| June 2026 | 124.4 thousands | 1.6 |
| May 2026 | 123.4 thousands | 1.3 |
| April 2026 | 122.1 thousands | 1.2 |
| March 2026 | 121.3 thousands | 1.4 |
| February 2026 | 121.1 thousands | 1.3 |
| January 2026 | 120.2 thousands | 1.3 |
| December 2025 | 120.5 thousands | 1.1 |
| November 2025 | 120.9 thousands | 1.0 |
| October 2025 | 121.2 thousands | 1.3 |
| September 2025 | 121.0 thousands | 2.0 |
| August 2025 | 120.1 thousands | 3.8 |
| July 2025 | 118.6 thousands | 3.5 |
| June 2025 | 122.4 thousands | 2.0 |
| May 2025 | 121.8 thousands | 2.6 |
| April 2025 | 120.6 thousands | 2.8 |
| March 2025 | 119.6 thousands | 1.8 |
| February 2025 | 119.6 thousands | 2.3 |
| January 2025 | 118.6 thousands | 2.2 |
| December 2024 | 119.2 thousands | 3.3 |
| November 2024 | 119.7 thousands | 3.4 |
| October 2024 | 119.7 thousands | 3.5 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-41620.PAYEMS.M.NSA.IND-90000000"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-41620.PAYEMS.M.NSA.IND-90000000",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```