# All Employees: Financial Activities — Charleston-North Charleston, SC (NSA)

All Employees: Financial Activities — Charleston-North Charleston, SC (NSA) was up 1.8% year on year in September 2026, compared with 1.4% in August 2026.
The level stood at 22.40 thousands.
Over the past ten years it has ranged from −3.2% (Apr 2020) to 18.7% (Mar 2023), averaging 4.5%.

- Source agency: U.S. Bureau of Labor Statistics (flat files)
- Makrognosis code: `US-16700.PAYEMS.M.NSA.IND-55000000`
- Frequency: monthly
- Units: thousands
- Coverage: 1990-01-01 to 2026-09-01 (441 observations)
- Page: https://makrognosis.robomacro.com/data/united-states/all-employees-financial-activities-charleston-north-charleston-sc-nsa

## Recent data

| Period | Value | Y/Y % |
|---|---:|---:|
| September 2026 | 22.40 thousands | 1.8 |
| August 2026 | 22.50 thousands | 1.4 |
| July 2026 | 22.50 thousands | 1.4 |
| June 2026 | 22.60 thousands | 0.0 |
| May 2026 | 22.10 thousands | −0.9 |
| April 2026 | 22.10 thousands | −1.8 |
| March 2026 | 21.90 thousands | 0.9 |
| February 2026 | 22.00 thousands | 1.9 |
| January 2026 | 21.90 thousands | 1.4 |
| December 2025 | 22.50 thousands | 5.1 |
| November 2025 | 22.30 thousands | 3.7 |
| October 2025 | 22.10 thousands | 3.3 |
| September 2025 | 22.00 thousands | 3.8 |
| August 2025 | 22.20 thousands | 5.2 |
| July 2025 | 22.20 thousands | 5.2 |
| June 2025 | 22.60 thousands | 8.7 |
| May 2025 | 22.30 thousands | 8.8 |
| April 2025 | 22.50 thousands | 10.8 |
| March 2025 | 21.70 thousands | 6.9 |
| February 2025 | 21.60 thousands | 5.9 |
| January 2025 | 21.60 thousands | 5.9 |
| December 2024 | 21.40 thousands | 2.4 |
| November 2024 | 21.50 thousands | 2.9 |
| October 2024 | 21.40 thousands | 2.4 |

## API

```
curl -H "X-API-Key: $MAKROGNOSIS_KEY" \
  "https://makrognosis.robomacro.com/v1/series/US-16700.PAYEMS.M.NSA.IND-55000000"

# Python
import requests
r = requests.get("https://makrognosis.robomacro.com/v1/series/US-16700.PAYEMS.M.NSA.IND-55000000",
                 headers={"X-API-Key": KEY})
obs = r.json()["observations"]
```